3x^2=100x+10000

Solution for 3x^2=100x+10000 equation:

3x^2=100x+10000

We move all terms to the left:

3x^2-(100x+10000)=0

We get rid of parentheses

3x^2-100x-10000=0

a = 3; b = -100; c = -10000;
Δ = b2-4ac
Δ = -1002-4·3·(-10000)
Δ = 130000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{130000}=\sqrt{10000*13}=\sqrt{10000}*\sqrt{13}=100\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-100\sqrt{13}}{2*3}=\frac{100-100\sqrt{13}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+100\sqrt{13}}{2*3}=\frac{100+100\sqrt{13}}{6}
$